21c^2+22c-24=

Solution for 21c^2+22c-24= equation:

Simplifying
21c2 + 22c + -24 = 0

Reorder the terms:
-24 + 22c + 21c2 = 0

Solving
-24 + 22c + 21c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-12 + -7c)(2 + -3c) = 0

Subproblem 1
Set the factor '(-12 + -7c)' equal to zero and attempt to solve:

Simplifying
-12 + -7c = 0

Solving
-12 + -7c = 0

Move all terms containing c to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -7c = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -7c = 0 + 12
-7c = 0 + 12

Combine like terms: 0 + 12 = 12
-7c = 12

Divide each side by '-7'.
c = -1.714285714

Simplifying
c = -1.714285714
Subproblem 2
Set the factor '(2 + -3c)' equal to zero and attempt to solve:

Simplifying
2 + -3c = 0

Solving
2 + -3c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3c = 0 + -2
-3c = 0 + -2

Combine like terms: 0 + -2 = -2
-3c = -2

Divide each side by '-3'.
c = 0.6666666667

Simplifying
c = 0.6666666667
Solution
c = {-1.714285714, 0.6666666667}